(1/8)^3x+4=(1/4)^-2x+4

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Solution for (1/8)^3x+4=(1/4)^-2x+4 equation: 



(1/8)^3x+4=(1/4)^-2x+4

We move all terms to the left:

(1/8)^3x+4-((1/4)^-2x+4)=0



Domain of the equation: 8)^3x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4)^-2x+4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/8)^3x-((+1/4)^-2x+4)+4=0

We calculate fractions


(-2x)/8^3x*4)^-2x+4))+(-8^3x/8^3x*4)^-2x+4))+4=0

We can not solve this equation

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